Question

find the number of terms in the sequence 4,12,20,- - -108​

Answer 1

a=4, d=12-4=8, an=108
Formula is
an=a+(n-1)d
108=4+(n-1)8
108-4=(n-1)8
104=(n-1)8
104/8=(n-1)
13=n-1
n=13+1
n=14
I hope it will help u