find the number of terms in the sequence 7,13,19.........151
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Answered by
3
Tn=a+(n-1)d
151 =7+n-1×6
151-7=n-1×6
144=n-1×6
144/6=n-1
24=n-1
25=n
151 =7+n-1×6
151-7=n-1×6
144=n-1×6
144/6=n-1
24=n-1
25=n
Answered by
3
Hey there ,
An = 151
a = 7
d = 6
an = a + (n-1)d
151 = 7 + (n-1)6
144 = 6n - 6
150 = 6n
n = 25
So, total numbers in the sequence is 25
Here , An = Last Number
a = first Number
d = common difference
Thanks!
An = 151
a = 7
d = 6
an = a + (n-1)d
151 = 7 + (n-1)6
144 = 6n - 6
150 = 6n
n = 25
So, total numbers in the sequence is 25
Here , An = Last Number
a = first Number
d = common difference
Thanks!
naeemathasneem:
Thank you very much. answer to my other questions. Please
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