Question

find the number of terms in the sequence 8 , 11 , 14.....86​

Answer 1

a=8
d=3
Let Tn=86
Tn=a+(n-1)d
86=8+(n-1)3
86=8+3n-3
81=3n
n=27
So the number of terms is 27

Answer 2

Answer:

The number of terms in the sequence 8 , 11 , 14.....86​ is 27

Step-by-step explanation:

$a=8\\d=3$

Let $T_{n}=86$

$T_n=a+(n-1)d$

$86=8+(n-1)3$

$86=8+3n-3$

$81=3n$

$n=27$

So, the number of terms is 27

Arithmetic sequence:

• A list of integers with a distinct pattern is known as an arithmetic sequence. It is an arithmetic sequence if you can subtract any number in the sequence from the one before it and get a value that is either constant or always the same.

• The common difference, symbolised by the letter dd, is the constant difference between every pair of subsequent or succeeding integers in a sequence. To transition from one phrase to another, we employ the common distinction. How? To get to the following term, start with the current term, then add the shared difference, and so on. The words in the sequence are created in this manner.

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