Question

Find the number of terms in the series 2, 5, 8, ... if the last term is 95.​

Answer 1

Answer:

term 32

Step-by-step explanation:

$a = 2. \: d = 3. \: tn = 95 \\ t _{n} = a + (n - 1)d \\ 95 = 2 + (n - 1)3 \\ 95 = 2 + 3n - 3 \\ 95 = - 1 + 3n \\ 95 + 1 = 3n \\ 96 = 3n \\ n = \frac{96}{3} \\ n = 32$