find the number of terms in the series 2+5+8+.... if the last term is 95
Answers
Answered by
7
a1=2
a2=5
d=3
an=95
an=a+(n-1)d
95=2+(n-1)3
93=3n-3
96=3n
n=96/3
n=32
a2=5
d=3
an=95
an=a+(n-1)d
95=2+(n-1)3
93=3n-3
96=3n
n=96/3
n=32
yuvraj1782:
merese bhi puch☺️
Answered by
0
Answer:
Step-by-step explanation:
Given series = 2 + 5 + 8 + 11 + … + 95 a = 2, d = 5 – 2 = 3, l = 95 Then, from l = a + (n – 1 )d ⇒ 2 + (n – 1) × 3 = 95 ⇒ 3(n – 1)= 95 – 2 ⇒ (n – 1) = 30/3 = 31 ⇒ n = 31 + 1 = 32 Hence, number of terms of the series is 32.Read more on Sarthaks.com - https://www.sarthaks.com/733745/in-an-a-p-2-5-8-11-if-last-term-is-95-then-find-the-number-of-terms-of-the-series
Similar questions