Find the number of terms in the sum of ( 3x² + 6xy + 5y2 ) and ( 3x + 4y - 13xy )
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Answer:
The number of terms in sum of ( 3x² + 6xy + 5y²) and ( 3x + 4y - 13xy ) is 5.
Step-by-step explanation:
Given:
Given : ( 3x² + 6xy + 5y²) and ( 3x + 4y - 13xy )
Find : the number of terms in the sum
( 3x² + 6xy + 5y²) + ( 3x + 4y - 13xy )
= 3x² + 6xy + 5y² + 3x + 4y - 13xy
=3x² + 6xy - 13xy + 5y² + 3x + 4y (rearrange the terms)
= 3x² + (6- 13)xy + 5y² + 3x + 4y
= 3x² - 7xy + 5y² + 3x + 4y
So, the number of terms in sum is 5.
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