Question

find the number of terms of AP 7,13,19.............................. 205.​

Answer 1

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

$= >n = 34$

$\Large{\underline{\underline{\bf{QuEsTiOn:-}}}}$

How many term are these in the AP 7,13,19,...........205?

$\huge\underline\mathbb{\red S\pink {0} \purple {L} \blue {UT} \orange {1}\green {ON :}}$

Given sequence is 7,13,19,...,205

Given sequence is 7,13,19,...,205The first term a=7 and

The common difference d=13−7=6

The last term is 205

Let the last term be the nth term.

We know that the nth term of the arithmetic progression is given by -

$= > a+(n−1)d$

$= > a+(n−1)d=205$

$= > 7+(n−1)×(6)=205</p><p></p><p>$

$= > 7− \: 6+6n=205</p><p></p><p>$

$= > 1+6n=205</p><p></p><p>$

$= > 6n=205−1$

$= > 6n = 204$

$= >n = \frac{204}{6}$

$= > n = 34$

$\sf\underline{\underline{\green{THEREFORE, \: }}}$

The number of terms in the given sequence is 34