Question

Find the number of terms of the arithmetic progression 6,3, 0, -3, ...-36.​

Answer 1

Step-by-step explanation:

n = ?

a = 6

d = 3 - 6 = -3

an = -36

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an = a + ( n - 1 ) d

-36 = 6 + ( n - 1 ) ( -3 )

-36 - 6 = -3n + 3

-42 = -3n + 3

-42 - 3 = -3n

-45 = -3n

n = -45/-3

n = 15

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