Question

find the number of terms of the finite AP -1,-5/6,-2/3,...,10/3.

Answer 1

Given:

a=-1

d=-5/6+1

=-5+6/6

=1/6

Given last term is 10/3

Let the Ap consist of n terms

a+(n-1)d=nth term

so:

a+(n-1)d=10/3

=-1+1/6(n-1)=10/3

=1/6(n-1)=10/3+1

=1/6(n-1)=13/3

=n-1=13/3*6

=n-1=26

=n=27.

27 terms make the AP.

Hope it helps:-)