Question

Find the number of terms of the finite AP
3,6, 9, .... 111.
​

Answer 1

Here, tn = 111

a = 3

d = 6-3 =3

n = ?

Formula: tn = a+(n-1)d

or, 111 = 3+(n-1)3

or, 111 =3+3n-3

or, 3n =111

or, n =111/3

=37 Ans.