Find the number of terms of the series 1/81,-1/27,1/9........-729.
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Given : 1/81,-1/27,1/9........ 729.
To Find : number of terms of the series
Solution:
1/81,-1/27,1/9........ 729.
Given series is an GP
a = 1/81
r = (-1/27)/( 1/81) = - 3
nth term of GP = arⁿ⁻¹
729 = (1/81)(-3)ⁿ⁻¹
=> 729 x 81 = (-3)ⁿ⁻¹
=> (3)⁶ * 3⁴ = (-1)ⁿ⁻¹ 3ⁿ⁻¹
=> 3¹⁰ = (-1)ⁿ⁻¹ 3ⁿ⁻¹
=> n - 1 = 10
=> n = 11
number of terms of the series = 11
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0
Answer:
term would be like this => 11
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