Question

find the number of the terms in each of the following AP's :

7,13,19,........,205.
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Answer 1

Hello Mate

Answer:

Your answer is =34

It's very easy question. Nothing to worry about this type of questions. Arithmetic Progression is the easiest chapter in class 10th.

Step-by-step explanation:

The AP= 7,13,19,......,205

Common difference (d)= 13-7= 6

Common difference (d)= 13-7= 6 First term (a)= 7

Common difference (d)= 13-7= 6 First term (a)= 7 Last term (l)= 205

No. of terms (n)= ??

Formula-

l= a+(n-1)d

By substituting the values we get

205=7+(n-1)6

205-7= (n-1)6

198=(n-1)6

198/6= n-1

33=n-1

33+1= n

34=n

Hope my answer helps you

Please mark my answer as BRAINLIEST ✌️

Answer 2

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

$= >n = 34$

$\Large{\underline{\underline{\bf{QuEsTiOn:-}}}}$

How many term are these in the AP 7,13,19,...........205?

$\huge\underline\mathbb{\red S\pink {0} \purple {L} \blue {UT} \orange {1}\green {ON :}}$

Given sequence is 7,13,19,...,205

Given sequence is 7,13,19,...,205The first term a=7 and

The common difference d=13−7=6

The last term is 205

Let the last term be the nth term.

We know that the nth term of the arithmetic progression is given by -

$= > a+(n−1)d$

$= > a+(n−1)d=205$

$= > 7+(n−1)×(6)=205</p><p></p><p>$

$= > 7− \: 6+6n=205</p><p></p><p>$

$= > 1+6n=205</p><p></p><p>$

$= > 6n=205−1$

$= > 6n = 204$

$= >n = \frac{204}{6}$

$= > n = 34$

$\sf\underline{\underline{\green{THEREFORE, \: }}}$

The number of terms in the given sequence is 34