Question

find the number of tiles of dimensions 1.6 x 0.9m required to cover a square floor of sides 18 m​

Answer 1

Step-by-step explanation:

$area \: of \: square \: floor \: = {18}^{2} \\ = 324 \: {m}^{2} \\ area \: of \: tiles = 1.6 \times 0.9 \\ = 1.44 \: {m}^{2} \\ no \: of \: tiles \: = \frac{area \: of \: square \: floor}{area \: of \: tiles} \\ = \frac{324}{1.44} \\ = 225 \: tiles$

Answer 2

Answer:

Area of the square floor = side × side

= 18m × 18m = 324m²

Area of 1 tile = 1.6m × 0.9 m = 1.44m²

Number of tiles required to cover the square floor

=

$\frac{area \: of \: floor}{area \: of \: tile} \\ \\ \: \: = \frac{324 {m}^{2} }{1.44 {m}^{2} } = \: 225$

✅ hence the required number of tiles is 225.

⛄ hope it helps you