find the number of tiles of dimensions 1m * 0.8m required to cover a floor of dimensions 80m * 120m.
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2
120*80*10/8
10000 tiles
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4
Answer:
12000
Step-by-step explanation:
Area of floor = (80 × 120) m² = 9600 m²
Area of tile = (1 × 0.8) m² = 0.8 m²
Number of tiles required = 9600 ÷ 0.8 = 12000
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