find the number of tiles required to cover the floor of the room 400 cm wide and 600 cm by squiered tiles.. if each tile is of 5cm then find the number of tiles to required to cover the floor of the room
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QUESTION
find the number of tiles required to cover the floor of the room 400 cm wide and 600 cm by squiered tiles.. if each tile is of 5cm then find the number of tiles to required to cover the floor of the room
ANSWER
Area of room=length * breadth=3*4=12Area of one tile =0.5*0.5=0.25number of tiles is given by the formula,number=area of room/area of one tileSo,Number= 0.2512 =48 Thus 48 tiles will be used to cover an entire floor
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Area of floor = length x breadth
= 400 x 600
= 240000 cm²
Area of tile = side²
= 5²
= 25 cm²
No. of tiles required = area of floor ÷ area of tile
= 240000 ÷ 25
= 9600
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