Question

find the number of times the perimeter and area of the square field is increased if side of the square field is doubled​

Answer 1

Answer:

let the side of square field be x

perimeter = 4x

now if you double the side that is 2x

New perimeter = 4*2x = 8x

Hence perimeter of square field is doubled

now area of square field= x^2

New side is 2x

Area of the triangle so formed = (2x)^2 = 4x^2

Hence the area becomes four times the original area

Step-by-step explanation:

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