find the number of triplets of prime number (p,q,r) satisfying 3p^4-5q^4-4r^2=26
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Answered by
2
Given : 3p⁴ - 5q⁴ - 4r² = 26
To find : number of triplets of prime numbers (p, q, r) satisfying
Solution:
3p⁴ - 5q⁴ - 4r² = 26
By Doing hit & Trial Method
p = 5
q = 3
r = 19
3p⁴ = 3(5)⁴ = 1875
5q⁴ = 5(3)⁴ = 405
4r² = 4(19)² = 1444
1875 - 405 - 1444
= 1875 - 1849
= 26
( 5 , 3 , 19) is the triplets of prime numbers (p, q, r) satisfying 3p⁴ - 5q⁴ - 4r² = 26
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Answered by
0
Answer:There are 3 triplets satisfying
Step-by-step explanation: The triplets are :
3,5,19,
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