Question

Find the number of tube force originating from point charge of 1.77 x
{10}^{ - 7}10−7
C. The dielectric constant of
medium surrounding the point charge is 4. (Eo= 8.85x10
{10}^{ - 12}{c}^{2}/nm2)

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Answer 1

Answer:

5000Nm²/C

Explanation:

FORMULA USED ; N = q/ eo*k

values = q = 1.77 * 10^-7

eo = 8.85 *10^-12

k = 4

putting the value

1.77*10^-7/8.85 *10^-12*4 = 5000Nm²/C

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Answer 2

Answer:

The tube force originating from the given point charge is 5000 Nm²/C

Explanation:

We are given a point charge $1.77 \times 10^-^7 \;C$, and we are asked to find the tube force originating from it.

We use the formula $F = \frac{q}{\epsilon_0 k}$ to find the tube force originating from the given point charge.

We have the values for the formula as follows -

$q = 1.77 \times 10^-^7\\\epsilon_0 = 8.85 \times 10^-^1^2\\k = 4$
We can figure the dielectric constant of the substance because of the material.

Substituting the values in the given formula, we can find the tube force as follows -

1.77*10^-7/8.85 *10^-12*4 = 5000Nm²/C

$F = \frac{q}{\epsilon_0 k}\\\\F = \frac{1.77 \times 10^-^7}{8.85 \times 10^-^1^2 \times 4}\\\\F = 5000 Nm^2\; C^-^1$

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