Question

Find the number of unpaired electrons present in the transition metal ion whose magnetic
moment is 4.9BM.

Answer 1

Answer: 4 is the answer

Explanation:

FORMULA to find magnetic moment is $\sqrt{n(n+2)}$ (n=number of unpaired electrons)

$\sqrt{n(n+2)}$=4.9 if we substitute 4 in the given formula then answer is 4.89≅4.9.

SHALL I GIVE YOU A SMALL TRICK,  

remember if the given magnetic moment is 1.732 then n=1

                                                                            2.45 then n=2

                                                                            3.87 then n=3

I HOPE YOU UNDERSTOOD THE TRICK (NUMBER OF UNPAIRED ELECTRONS WITHOUT OPTION VERIFIFCATION WE CAN SAY JUST BY KNOWING THE NUMBER BEFORE DECIMAL POINT)

HOPE YOU UNDERSTOOD .................

THANK YOU.