find the number of values of X in the interval 0,3π
satisfying the equation 2 sin square x + 5 sin x minus 3 equal to zero
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Answered by
33
π/6;5π/6;8π/3;13π/6
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Answered by
11
Answer: π/6, 5π/6, 13π/6, 17π/6
Step-by-step explanation:
2sin^2x+5sinx-3=0
(2sinx-1)(sinx+3)=0
Which gives. sinx=1/2, -3
Neglect sinx=-3 {as not possible (-1<=sinx<=1)}
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