Question

Find the number of ways in which 21 balls can be distributed among 3 persons such that each person does not receive less than 5 football

Answer 1

There are seven ways in which balls can be distributed
5+5+11=21
5+6+10=21
5+7+9=21
5+8+8=21
6+6+9=21
6+7+8=21
7+7+7=21
hope it helps
please, mark brainliest

Answer 2

Answer:

28

Step-by-step explanation:

let x,y,z be the number of balls received by the three persons,

then,

   x≥5, y≥5, z≥5 and x+y+z=21

let, u≥0,v≥0,w≥0

x+y+z=21

u+5+v+5+w+5=21

u+v+w=6

we know that,

No of ways = n+r-1Cr-1

=6+3-1C3-1

=8C2

=28