Question

find the number of ways in which 5 boys and 4 girls can be seated in a row so that no two girls are together.

Answer 1

Answer:

12

Step-by-step explanation:

1 such way is possible where boys and girls seat alternately.

if in any case the 2 boys seat beside each other then any 2 of the girls will also be altogether.

Next case is

where 2 boys are seated beside each other and at the one extreme ends girls are seated.

G B G B B G B G B (here G stands for girls and B for boys)

G B B G B G B G B

G B G B G B B G B

B G B G B B G B G

B G B B G B G B G

B G B G B G B B G

So 6 possible cases

Next case is

where 2 boys seated beside each other are at one of the extreme ends.

So we can hv 2 such possible seating arrangemnets. It is

B B G B G B G B G

G B G B G B G B B

So 2 possible cases

Next case is

If three boys are seated altogether, then girls must be at extreme ends.

We can hv 3 such cases they are

G B G B B B G B G

G B B B G B G B G

G B G B G B B B G

So 3 possible cases

4 or more boys cannot be seated altogether .

So we get total of 12 possible cases.

Pls mark brainliest