Question

Find the number of ways in which arrange the letters of the word akshay such that vowels do not come in the beginning

Answer 1

Answer:

336

Step-by-step explanation:

AKSHAY

The no. of letters = 6

Since two A s are repeated

∴ Repeated letters = 2

Total arrangements of the words AKSHAY

$=\frac{6!}{2!}$

$=\frac{6\times 5\times 4\times 3\times 2!}{2!}$

$=360$

Now if two As are taken together and placed at the beginning then the rest 4 letters can be arranged in 4! ways

$4!=24$

Therefore, number of arrangements where two vowels do not come together

$=360-24$

$=336$

Hope this helps.