Find the number of ways of arranging 6 boys and 6 girls around a circular table so that
(i) all the girls are together (ii) no two girls are together
(iii) boys and girls come alternately
Answers
Answered by
1
Step-by-step explanation:
6 boys and 6 girls
No of ways all girls sit together =5!×6!
5! for arranging girls and 6! for arranging boys
No. of ways no two girls sit together =5!×6!×
6
C
6
=5!×6!
5! for girls and 6! for boys
No. of ways boys and girls sit alternatively =5!×6!×
6
C
6
=5!×6!
5! for girls and 6! for boys
Answered by
1
5 girls and 6 boys
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