Math, asked by eswar386, 7 months ago

Find the number of ways of arranging 6 boys and 6 girls around a circular table so that

(i) all the girls are together (ii) no two girls are together

(iii) boys and girls come alternately​

Answers

Answered by huluhuli9
1

Step-by-step explanation:

6 boys and 6 girls

No of ways all girls sit together =5!×6!

5! for arranging girls and 6! for arranging boys

No. of ways no two girls sit together =5!×6!×

6

C

6

=5!×6!

5! for girls and 6! for boys

No. of ways boys and girls sit alternatively =5!×6!×

6

C

6

=5!×6!

5! for girls and 6! for boys

Answered by paturiyasaswini7
1
5 girls and 6 boys

Mark me as brainlist
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