Question

find the number of ways of arranging 8 persons around a circular table if two particular persons wish to sit together​

Answer 1

8c2=8*7*6*5*4*3*2*1/6*5*4*3*2*1*2*1=28 ans

Answer 2

Total arrangments are $360$

Explanation:

If clockwise and anticlockwise circular permutations are considered to be same, then it is $\frac{(n-1)!}{2}$  

$=\frac{(n-1)!}{2}$

$=\frac{(7-1)!}{2}$

$\frac{6!}{2} = 6\times5\times4\times3\times1 = 360$  

so the total arrangments are $360$.