Find the number of ways we can pick 2 milk chocolate bars and 3 dark chocolate bars from a box of 10 milk chocolate bars and 8 dark chocolate bars, considering that the elements are distinct and the arrangement is without replacement. (I would prefer if you use combinations or permutations)
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total milk chocolate = 10
total dark chocolate = 8
we want 2 milk chocolate and 3 dark chocolate
so
¹⁰C2 * ⁸C3
45*56
=2520
if my answer is correct like it so that i come to know!!
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