Question

find the number of years for which the compound interest of rupees9000 is rupees1890,at the rate of 10 p.c.p.a?​

Answer 1

Answer:

2 years

Given,

Compound interest= 1890, Principal = 9000, Rate r = 10 years, CI = 1890.

To Find,

Number of years.

Solution,

• CI = A - P

==> 1890 = A - 9000

==> 1890 + 9000 = A

==> 10890 = A.

Now,

• A = P(1 + r/100)^n

==> 10890 = 9000(1 + 10/100)^n

==> 10890/9000 = (110/100)^n

==> (1.21) = (1.1)^n

==> (1.1)^2 = (1.1)^n

==> n = 2 .

Result,

Therefore, the number of years = 2.

Answer 2

Answer:

2 yrs is the correct answer of this question