find the number of years for which the simple intrest on a sum of money is 1/9 th of the principal and the number of years is equal to the rate of intrest percent per annum.
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Answer:
Time period is 10/3 years or 10 years and 4 months.
Step-by-step explanation:
Let P = principal; R = rate of interest (% per year); T = number of years
SI = P*R*T/100
We are given that
SI = 1/9*P and T = R
Therefore,
P/9 = P*T*T/100 [Because T = R]
1/9 = T^2/100
T^2 = 100/9
T = 10/3 [Time period cannot be negative so -10/3 is not admissible]
The number of years = 10/3 years = 10 years and 4 months
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