Question

Find the number of zeroes of polynomial x square -1

Answer 1

Answer:

The number of zeros are two.

The zeroes are -1 and 1

${x}^{2} - 1 = 0 \\ {x}^{2} = 1 \\ x = \sqrt{1} \\ x = + 1 \: and \: - 1$

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Answer 2

$\huge{ \mathtt{ \fbox{Solution :) }}}$

Given ,

• The polynomial is (x)² - 1

Thus ,

$\sf \hookrightarrow {(x)}^{2} - 1 = 0 \\ \\ \sf \hookrightarrow</p><p> {(x)}^{2} - {(1)}^{2} = 0 \\ \\ \sf \hookrightarrow</p><p>(x + 1) (x - 1) = 0 \\ \\ \sf \hookrightarrow </p><p>x = -1 \: or \: x = 1</p><p></p><p></p><p>$

Hence , the roots of the given polynomial are -1 and 1

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