find the number of zeroes of the following polynomial p(x)= x-x²-¹
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Answer:
The number of zeros of a polynomial is equal to the degree of the polynomial which in this case is 2
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Step-by-step explanation:
First you should write it in standard form
x²-1 + x = x + x = 2x
let p(x) = 0 so
2x = 0
x = 0/2
x = 0
As it is a linear polynomial It has only one zero i.e 0
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