Find the number of zeroes of the given polynomial q(y) = y2 – 1. Also find their values.
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Answered by
12
q(y) = y²-1
Since q(y) is a second degree polynomial it will have 2 zeroes
q(y) = y²-1 = y² - 1²
= (y+1)(y-1)
Therefore the zeroes of the polynomial are
y + 1 = 0 and y - 1 = 0
y = -1 and y = 1
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Answered by
3
Answer:
y= -1 or 1
Step-by-step explanation:
q(y) = y²-1
Since q(y) is a second degree polynomial it will have 2 zeroes
q(y) = y²-1 = y² - 1²
= (y+1)(y-1)
Therefore the zeroes of the polynomial are
y + 1 = 0 and y - 1 = 0
y = -1 and y = 1
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