find the number of zeroes of x2-1
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Step-by-step explanation:
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x²+1=0x²=-1x=√-1x=i ∉R(or)x=-b± √b²-4ac/2ahere a=1 b=0c=1x=0 ± √0-4/2(1)=0±√-4/2=±2 ... More
Answered by
1
Answer:
Step-by-step explanation:
x²-1=0
x²=1
x=+1,-1,√1
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