find the number of zeros and the real zeros of p(X)=x³-2x²
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Answered by
2
P(x) = x³-2x²
= 2³-2*2²
=8-2*4
=8-8
=0
= 2³-2*2²
=8-2*4
=8-8
=0
siddharth2983:
from where the 2 will come??
Answered by
3
p(×)=×3-2×2
=23-2×22=
=8-2*24
=8-8=0
=23-2×22=
=8-2*24
=8-8=0
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