Question

find the number of zeros at the end of 1^20×2^20×3^20×4^20........×38^20.​

Answer 1

Answer:

5

Step-by-step explanation:

1^20×2^20×3^20×4^20-5-×38^20

Answer 2

Answer:

160+7=167

Step-by-step explanation:

1*2*3*4....*38=8times

rest 5 =160 times