find the number of zeros of the given polynomial and also find their values q(y)=y^2-1
Answers
Answered by
0
Answer:
The values of zeros are -1 and 1.
Step-by-step explanation:
y² - 1 = 0
y² - 1² = 0
Use formula: a² - b² = (a + b)(a - b)
(y + 1)(y - 1) = 0
y + 1 = 0 ; y - 1 =0
y = -1 ; y = 1
Similar questions