find the number of zeros of x square + 4 x + 2
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The zeroes are -2 + √2 and -2 - √2
Step-by-step explanation:
Given Expression:
x^2+4x+2x
2
+4x+2
We have to find zeroes of the given expression.
For this we put given expression equal to 0
So,
x^2+4x+2=0x
2
+4x+2=0
Now to find zero we solve the quadratic equation using quadratic formula,
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}x=
2a
−b±
b
2
−4ac
x=\frac{-4\pm\sqrt{4^2-4\times1\times2}}{2\times1}x=
2×1
−4±
4
2
−4×1×2
x=\frac{-4\pm\sqrt{16-8}}{2}x=
2
−4±
16−8
x=\frac{-4\pm2\sqrt{2}}{2}x=
2
−4±2
2
x=-2\pm\sqrt{2}x=−2±
2
Therefore, The zeroes are -2 + √2 and -2 - √2
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