find the number, say X such that when 6 is subtract from 3times the number, the result is 6 more than twice the number.?
Answers
Answered by
3
3x-6=6+2x
3x-2x=6+6
x=12
3x-2x=6+6
x=12
Answered by
3
let the number be x
when 6 is subtracted from the number then equation will be -> 3x-6
when the result of the above equation is 6 more of the twice of the number then the equation will be -> 6+2x
equate the equation first and second
3x-6=6+2x
3x=12+2x
3x-2x=12
x=12
when 6 is subtracted from the number then equation will be -> 3x-6
when the result of the above equation is 6 more of the twice of the number then the equation will be -> 6+2x
equate the equation first and second
3x-6=6+2x
3x=12+2x
3x-2x=12
x=12
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