Question

find the number such that one is 6 times the other and their sum is 49​

Answer 1

Answer:

Let one number be x.

Then, other number = 6x

Atq,

$\: \: \: \: \: \: \: \: x + 6x = 49 \\ = > 7x =4 9 \\ = > x = \frac{49}{7} \\ = > x =7$

Hence, the required numbers are 7 and (6×7)=42

Answer 2

$\huge\underline\mathfrak\red{Answer:}$

Let One number be= x

Let Other number be= 6x

Their original sum = 49

Their sum = x+6x = 7x

According to the question-

$7x = 49$

$x = \frac{49}{7} = 7$

x=7

6x=7 x 6=42