Find the number such that the mean proportional between them is 18 and third proportional to them is 144
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Answered by
41
Helloo!!
x/18 = 18/y
xy = 18*18
x/y = y/144
x = (y^2)/144
putting the value of x
we get,
((y^2)/144)*y = (y^3)/144 = 18*18
y^3 = 18*18*144
y = 36
x = 36*36/144
x = 9
Therefore numbers are 9 and 36
hope this helps you
x/18 = 18/y
xy = 18*18
x/y = y/144
x = (y^2)/144
putting the value of x
we get,
((y^2)/144)*y = (y^3)/144 = 18*18
y^3 = 18*18*144
y = 36
x = 36*36/144
x = 9
Therefore numbers are 9 and 36
hope this helps you
IWannaStudy:
What have you done in 5th step?
Answered by
5
Answer:
Helloo!!
x/18 = 18/y
xy = 18*18
x/y = y/144
x = (y^2)/144
putting the value of x
we get,
((y^2)/144)*y = (y^3)/144 = 18*18
y^3 = 18*18*144
y = 36
x = 36*36/144
x = 9
Therefore numbers are 9 and 36
hope this helps you
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