Find the number , surn and product of divisors of the following numbers iv 3600
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If the prime factorisation of a composite number N=a
m
×b
n
×c
o
...., the number of its factors =(m+1)(n+1)(o+1)....
Prime factorisation of 3600=2
4
×3
2
×5
2
So, number of factors of 3600=(4+1)×(2+1)×(2+1)=5×3×3=45
From these factors, 1 and 3600 are factors too, so remaining number of factors 45−2=43
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