Find the number that if we subtract thrice of it from each of the two terms of the ratio 49/69 , the ratio becomes 2/3
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Let the number be a
49-3x/69-3x=2/3
49-3x=138-6x/3
147-9x=138-6x
147-138=9x-6x
9=3x
x=3
Then the number is 3
49-3x/69-3x=2/3
49-3x=138-6x/3
147-9x=138-6x
147-138=9x-6x
9=3x
x=3
Then the number is 3
theredkillerx:
Thank you very much
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