Question

Find the number to be added to the polynomial x^2-5x+4,so that 3 is the zero of the polynomial

Answer 1

${x}^{2} - 5x + 4$
${x}^{2} - 1x - 4x + 4$
$x(x - 1) - 4(x - 1)$
$(x - 1)(x - 4)$
$x = 1 \: or \: 4$

Answer 2

$\huge {\underline {\underline {\underline {\pink{\mathfrak{SoLuTiOn}}}}}}$

${x}^{2} - 5x + 4$

${x}^{2} - 1x - 4x + 4$

$x(x - 1) - 4(x - 1)$

$(x - 1) (x - 4)$

$x = 1$

${or}$

$x = 4$