find the number when added to each term of the ratio 27 :35, changes the ratio to 4 : 5
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Let the number be ( k )
According to the question :
= 5( 27 + k ) = 4( 35 + k )
= 135 + 5k = 140 + 4k
= 5k - 4k = 140 - 135
= k = 5
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Let the number be ( k )
According to the question :
= 5( 27 + k ) = 4( 35 + k )
= 135 + 5k = 140 + 4k
= 5k - 4k = 140 - 135
= k = 5
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