Question

find the number which added to 22 and 40 gives two number with product 1288...please some body help me with this quadtratic equation

Answer 1

Let the no. be x.
(x+22)(x+40)=1288
on solving,
x2 +22x +40x +880=1288
x2 +62x +880=1288
x2 +62x -408=0
x2 -6x +68x -408=0
x(x-6) +68(x-6)=0
(x+68)(x-6)=0
x=-68,6

Answer 2

let the number be x
(x+22)(x+40)=1288
x(x+40)+22(x+40)=1288
x²+40x+22x+880=1288
x²+62x+880=1288
x²+62x-408=0
x²+(68-6)x-408=0
x²+68x-6x-408=0
x(x+68)-6(x+68)=0
(x+68)(x-6)=0
either
x=-68
or
x=6