Find the number which divides 204 and 434 leaving remainder 5 in each case
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Prime factorization of 429 = 3 * 11 * 13. = 33. Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33.
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Answered by
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Answer:
Step-by-step explanation:
Given that the numbers 203 and 434 leaving remainder 5 in each case respectively.
The numbers that are exactly divisible are 203 - 5 = 198 and 434 - 5 = 429.
Prime factorization of 198 = 2 * 3 * 3 * 11
Prime factorization of 429 = 3 * 11 * 13.
HCF(198,429) = 3 * 11
= 33.
Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33.
Hope this helps!
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