Question

Find the number which is divisible by the difference of 100x+y and 100y+x​

Answer 1

Step-by-step explanation:Difference of any three digit number by its reversing number is always a exact product of 9. i.e divisible by 9.Let 100x+10y+z be the number; its reverse is 100z+10y+x.Difference of the number will be:(100x+10y+z)−(10z+10yb+x) = (100−1)x + (10−10)y + (1−100)z= 99x−99z = 99(x−z)So the difference of any three digit number with its reverse number is divisible by 9. ( Also 11 and 99).

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