Find the number which is greater than one fifth of itself by 12
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Answered by
12
Let the number be x.
A/q
![x = \frac{x}{5} + 12 \\ x - \frac{x}{5} = 12 x = \frac{x}{5} + 12 \\ x - \frac{x}{5} = 12](https://tex.z-dn.net/?f=x+%3D++%5Cfrac%7Bx%7D%7B5%7D++%2B+12+%5C%5C+x+-++%5Cfrac%7Bx%7D%7B5%7D++%3D+12)
![\frac{4x}{5} = 12 \\ x = \frac{12 \times 5}{4} \\ x = 15 \frac{4x}{5} = 12 \\ x = \frac{12 \times 5}{4} \\ x = 15](https://tex.z-dn.net/?f=+%5Cfrac%7B4x%7D%7B5%7D++%3D+12+%5C%5C+x+%3D++%5Cfrac%7B12+%5Ctimes+5%7D%7B4%7D++%5C%5C++x+%3D+15+)
A/q
Answered by
0
hello...
let the number be "n"
ATGC...
n/5 +12 = n
n + 60 /5 = n
n + 60 = 5n
60 = 5n - n
60 = 4n
n = 60/4
n = 15
:)
let the number be "n"
ATGC...
n/5 +12 = n
n + 60 /5 = n
n + 60 = 5n
60 = 5n - n
60 = 4n
n = 60/4
n = 15
:)
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