find the number which should be added to x²+x+3 so that the resulting polynomial is completly divisible by (x+3)
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Step-by-step explanation:
let the repquired number be k.
let
f(x)=x²+x+3+k
it is given that f(x) is divisible by (x+3)
therefore,
remainder=0
f(-3)=0
(-3)²+(-3)+3+k=0
9-3+3+k=0
9+k=0
k= -9
thus the required no. is -9
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