Question

find the number which when diminished by 9 is 53​

Answer 1

First find the smallest number divisible by 12,16,18,21 and 28.

It is the LCM of these numbers.

12=2×2×3=2

2

×3

16=2×2×2×2=2

4

18=2×3×3=2×3

2

21=3×7

28=2×2×7=2

2

×7

LCM=2

4

×3

2

×7=1008

Required number = (L.C.M. of 12, 16, 18, 21, 28) +7

=1008+7

=1015

So the required number is 1015.

If you diminish by 7, it will be divisible by all the given numbers

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