Question

find the number which when divided by 47 gives 23 as quotient and 37 as remainder. Find the HCF of that number and 47.

Answer 1

THE NUMBER IS DIVIDEND

DIVIDEND = DIVISOR × QUOTIENT + REMAINDER

.: DIVIDEND = (47 × 23) +37
= 1081 + 37
= 1118

HCF OF 1118 AND 47 IS 1...

HOPE THIS ANSWER HELPS ....✌

Answer 2

to get this answer, first we have to multiply 47 with 23 = 1081  and add 37 with
1081 and we get 1118 . HCF of 47 and 1118 is 1